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If (a^(logb x))^2-5\ a^(logb x)+6=0, whe...

If `(a^(log_b x))^2-5\ a^(log_b x)+6=0,` where `a >0, b >0\ &\ a b!=1,` then the value of `x` can be equal to (a) `2^(log_b a)` (b) `3^(log_a b)` (c) `b^(log_a2)` (d) `a^(log_b3)`

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