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The expression 1/(log5 3)+1/log6 3-1/log...

The expression `1/(log_5 3)+1/log_6 3-1/log_10 3`simplifies to

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For N>1, then product (1)/(log_(2)N)*(1)/(log_(N)8)*(1)/(log_(32)N)*(1)/(log_(N)128) simplifies to (a) (3)/(7) (b) (3)/(7ln2) (c) (3)/(5ln2)(d)(5)/(21)

The value of the expression (1)/(log_(4)(18))+(1)/(2log_(6)(3)+log_(6)(2))+(2)/(log_(3)(18)')

log_10(log_2 3) + log_10(log_3 4) + log_10(log_4 5) + ........ + log_10 (log_1023 1024) simplifies to

(log_(2)3)(log_(1/3)5)(log_(4)6)<1

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BANSAL-LOGARITHM-All Questions
  1. The expression x=log2log9sqrt(6+sqrt(6+sqrt(6+.........oo))) simplifie...

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  2. The number N= 2^ (log2 3·log3 4.log4 5....... log99 100) simplifies to

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  3. The expression 1/(log5 3)+1/log6 3-1/log10 3simplifies to

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  4. The number N=sqrt(2+sqrt5-sqrt(6-3sqrt5+sqrt(14-6sqrt5) simplifies to

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  5. The value(s) of x , which does not satisfy the equation log2^2(x^2-x...

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  6. The value of x satisfying the equation 2^(log2e^(In^5log 7^(log10^(log...

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  7. he number N=(1/(log2pi)+1/(log6pi)) is less then

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  8. Let I=(log3 4+log2 9)^2-(log3 4-log2 9)^2 and m=(0.8)(1+9^(log3 8))^...

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  9. Let A denotes the value of log10 {(ab+sqrt((ab)^2-4(a+b)))/2}+log10 {l...

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  10. If k^(log2 5)=16 , find the value of k^((log2 5)^2)

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  11. For x , y in NN , if 3^(2x-y+1)=3^(y-2x+1)-8 and log6|2x^2y-x y^2|=1+...

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  12. Let log2x+log4y+log4z=2; log9x+log3y+log9z=2; log(16)x+log(16)y+log4z...

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  13. Find the value of x satisfying (log)(10)(2^x+\ x-41)=x\ (1-(log)(10)...

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  14. Positive numbers x , y\ and\ z satisfy x y z\ =\ 10^(81) and (log(10)x...

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  15. Find the number of integral solution of the equation log(sqrt(x))(x+|x...

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  16. Suppose p , q ,r and s in NN satisfying the relation p+1/(q+1/(r+1/s))...

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  17. If x and y are real numbers, such that 2log(2y-3x)=logx+logy, then fin...

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  18. given log(10)(34.56) find the value of the following log(10)(3.456) , ...

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  19. If log(10)2=0.3010 ,\ log(10)3=0.4771. Find the number of integers in ...

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  20. If log(3)M=a1+b1 and log5M=a2+b2 where a1,a2 in N and b1,b2 in [0,1). ...

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