A random variable X has following probability distribution
`{:(X=x,1,2,3,4,5,6),(P(X=x),K,3K,5K,7K,8K,K):}`
Then `P(2leX lt 5)`= . . . .

A random variable X has the following distribution {:(x:,1,2,3,4),(P(X=x):,k^(2),3k^(2),5k^(2),7k^(2)):} The value of k is

A random variable X has the following distribution {:(x:,1,2,3,4),(P(X=x):,k^(2),3k^(2),5k^(2),7k^(2)):} The value of k is

A random variable X has the probability distribution given below. Its variance is {:(X,1,2,3,4,5),(P(X=x)k,2k,3k,2k,k,):}

A random variable X has the following distribution {:(X=x_(1):,1,2,3,4),(P(X=x_(1)):,k,2k,3k,4k):} The value of k and P(X lt 3) are equal to

A random variable X has the following distribution {:(X=x_(1):,1,2,3,4),(P(X=x_(1)):,k,2k,3k,4k):} The value of k and P(X lt 3) are equal to

A random variable x has the following distribution . {:(x,1,2,3,4),(f(x),k,2k,4k,3k):} Then its mean is :

A random variable X has the following probability distribution: Determine (i) k (ii) P(X 6) (iv) P(0

A random variable has the following probability distribution: X=x_(i):12 34P(X=x_(i)):k2k3k4k Write the value of P(X>=3)

A random variable X has the following probability distribution. i. k ii. P(X lt 3) iii. P (0 lt X lt 5)

A random variable X has the following probability distribution. Find (i) k (ii) Mean (iii) P(0 lt X lt 5)