The circle `4x^(2)+4y^(2)-12x-12y+9=0`

What is the radius of the circle 4x^(2) +4y^(2) -20x +12y -15=0 ?

Find equation of circle concentric with circle 4x^(2)+4y^(2)-12x-16y-21=0 and of half its area.

The radical centre of the circles x^(2) + y^(2)- 2x + 6y = 0 , x^(2) + y^(2) - 4x - 2y + 6 = 0 , x^(2) + y^(2) - 12x + 12y + 30 = 0 is

The circles x^(2)+y^(2)-12x+8y+48=0, x^(2)+y^(2)-4x+2y-4=0 are

The circles x^(2)+y^(2)-12x+8y+48=0, x^(2)+y^(2)-4x+2y-4=0 are

If the circle x^(2) + y^(2) - kx - 12y + 4 = 0 touches the X-axis then : k =

The inverse of the point (1,2) with respect to circle x^(2)+y^(2)-4x-6y+9=0

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.

The equation of the normal at (1,2) to the circle x^(2)-y^(2)-4x-6y-12=0 is

One of the diameters of the circle x^(2)+y^(2)-12x+4y+6=0 is given by