" 5."(1+y^(2))dx=(tan^(-1)y-x)dx

Solve :(1+y^(2))dx=(tan^(-1)y-x)dy

Solve the following differential equations (i) (1+y^(2))dx = (tan^(-1)y - x)dy (ii) (x+2y^(3))(dy)/(dx) = y (x-(1)/(y))(dy)/(dx) + y^(2) = 0 (iv) (dy)/(dx)(x^(2)y^(3)+xy) = 1

Solve : (1+y^(2))dx=(tan^(-1)y-x)dy , given that y=0 when x = -1.

The solution of (1 + y^(2)) dx = (Tan^(-1) y -x) dy is

SolveL (1+y)^2dx=(tan^(-1)y-x)dy , given that y= 0 when x= -1.

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)

If log (x^(2)+y^(2))=tan^(-1)((y)/(x)), then show that (dy)/(dx)=(x+y)/(x-y)

The solution of the differential equation (1+y^(2)) tan^(-1) x dx + y(1+x^(2)) dy = 0 is