Assertion (A): Equivalent weights of NaCl, NaOH, KCl, KBr etc. are equal to their molecular weights
Reason (R): Only one electron take part in electrode reaction.

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation Equivalent weight of MnO_(4)^(-) in acidic, basic and neutral media are in the ratio of

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation The equivalent weght of As_(2),S_3 in the following reaction As_(2)S_(3) + H^(+) + NO_(3)^(-) rarr NO + H_(2)O + AsO_(4)^(3-) + SO_(4)^(2-) is related to its molecular weight as

The equivalent weights of oxidising and reducing agents can be calculated by the number of electrons gained or lost. The equivalent weight of an oxidising agent is the number of parts by weight of the substance which gains one electron. Thus, it is equal to the molecular weight of the substance divided by the number of electrons gained in the balanced chemical equation. Similarly, equivalent weight of a reducing agent is equal to the molecular weight divided by the number of electrons lost as represented in the balanced chemical equation The equivalent weight of barium in BaCrO_4 used as an oxidising agent in acidic medium is (At, wt, of Ba - 137.34)

Assertion : Equivalent weight of a base =("Molecular weight")/("Acidity") Reason : Acidity is the number of replaceable hydrogen atoms in one molecule of the base.

Assertion (A) : The equivalent weights of nitric acid and crystalline oxalic acid are same. Reason (R ) : The basicity is same for both the acids.

Fill in the blanks by choosing the appropriate word/words from those given in the brackets: (ionic conduction, electronic conduction, anode, cathode, one coulomb, one faraday of their equivalent weights, of their molecular weights, decoration, Avogadro's number, proton number, loss of electrons, gain of electrons, can, cannot, e.m.f., negative, positive, greater, H_(2) , sodium, less, more, bad, good, increases, decreases electrode potential, negative, positive, greater, less, H_(2), O_(2) , more). Electrochemical equivalent is the weight of substance liberated when ......... electricity is passed through the electrolyte.

Fill in the blanks by choosing the appropriate word/words from those given in the brackets: (ionic conduction, electronic conduction, anode, cathode, one coulomb, one faraday of their equivalent weights, of their molecular weights, decoration, Avogadro's number, proton number, loss of electrons, gain of electrons, can, cannot, e.m.f., negative, positive, greater, H_(2) , sodium, less, more, bad, good, increases, decreases electrode potential, negative, positive, greater, less, H_(2), O_(2) , more). Solid NaCl is a ............. conductor of electricity.

Fill in the blanks by choosing the appropriate word/words from those given in the brackets: (ionic conduction, electronic conduction, anode, cathode, one coulomb, one faraday of their equivalent weights, of their molecular weights, decoration, Avogadro's number, proton number, loss of electrons, gain of electrons, can, cannot, e.m.f., negative, positive, greater, H_(2) , sodium, less, more, bad, good, increases, decreases electrode potential, negative, positive, greater, less, H_(2), O_(2) , more). When 96,500 coulombs is divided by the charge on the electron in coulomb, the answer is equal to.........