the system of equations `x+y+z=4,2x+5y-2z=3,x+7y-7z=5` has no solution.

If the system of equations x+2y+3z=1, 2x+ky+5z=1, 3x+4y+7z=1 has no solutions, then -

The system of equations x +2y+3z=1, x-y+4z=0, 2x+y+7z=1 has

Examine the consistency of the following systems of equations x+y+z=4,2x+5y-2z=3,x+7y-7z=5 , and if consistent find the complete solutions.

" The number of solutions of the system of equations "x+y+z=4,2x+5y-2z=3" and "x+7y-7z=5" is /are "

The system of equations x+y+z=6, x+2y+3z=14, x+4y=7z=30 has

The system of equations 4x+y+2z=5, x-5y+3z=10, 9x-3y+7z=20 has

Solve the system of equations 2x+4y-z=0,x+2y+2z=5,3x+6y-7z=2 by Gauss Jordan Method.

The number of solutions of the system of equations x+y+z = 4, 2x + 5y – 2z = 3 and x + 7y – 7z = 5, is /are a)0 b)1 c)2 d)infinite

By Cramer's rule solve the system of equations 3x+4y+5z=18,2x+y+8z=13,5x-2y+7z=20 .