A current of `30A` is flowing in a vertical straight wire. If the horizontal component of earths magnetic is `2xx10^(-5)T`, then the position of null point will be

Explain the horizontal and vertical components of earth's magnetic field.

A long vertical wire carriers a current of 10 amperes flowing upwards through it at place where the horizontal component of the earth's magnetic induction is 0.3 gauss. Then the total magnetic induction at a point 5 cm from the wire due magnetic north of the wire is

A current of 5A flows downwards in a long straight vertical conductor and the earth's horizontal flux density is 2 xx 10^(-7)T then the neutral point occurs

A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0ms^-1 at right angles to the horizontal component of the earth's magnetic field, 0.30xx10^-4Wb m^-2 What is the direction of the emf?

A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 ms, at right angles to the horizontal component of the earth's magnetic field, 0.30 xx 10^(-4)Wb m^(2) What is the direction of the emf?

A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 ms, at right angles to the horizontal component of the earth's magnetic field, 0.30 xx 10^(-4)Wb m^(2) Which end of the wire is at the higher electrical potential?

At a certain place the horizontal component of earth's magnetic field is (1)/(sqrt3) times the vertical component. The angle of dip at that place is

A long vertical wire in which a current is flowing produces a neutral point with the earth's magnetic field at a distance of 5 cm from the wire. If the horizontal component of the earth's magnetic induction is 0.18 gauss, then the current in the wire is