A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased

A parallel-plate capacitor is charged from a cell and then disconnected from the cell. The separation between the plates is now double.

A parallel plate capacitor is charged completely and then disconnected from the battery. IF the separation between the plates is reduced by 50% and the space between the plates if filled with a dielectric slab of dielectric constant 10, then the potential difference between the plates

A parallel plate capacitor is charged and then isolated. On increasing the plate separation

A parallel plate capacitor is charged and then isolated. On increasing the plate separation

A parallel- plate capacitor is charged from a cell and then isolated from it. A dielectric slab of dielectric constant K is now introduced in the region between the plated, filling half of it. The electric intensity in the diaelectric is E_(1) and that in air is E_(2) .

A parallel plate capacitor is charged with a battery and then separated from it. Now if the distance between its two plates is increased, what will be the changes in electric charge, potential difference and capacitance respectively ?

STATEMENT-1: A parallel plate capacitor is charged by a battery. The battery is then disconnected. If the distance the plates is increased, the enegry strored in the capacitor will decrease. STATEMENT-2: Work has to be done to increase the separation between the plates of a charged capacitor.