At the moment t=0 particle leaves the origin and moves in the positive direction of the x-axis. Its velocity varies with time as `v=10(1-t//5)`. The dislpacement and distance in 8 second will be

At the moment t=0 a particle leaves the origin and moves in the positive direction of the x-axis. Its velocity varies with time as v=v_0(1-t//tau) , where v_0 is the initial velocity vector whose modulus equals v_0=10.0cm//s , tau=5.0s . Find: (a) the x coordinate of the particle at the moments of time 6.0 , 10 , and 20s , (b) the moments of time when the particles is at the distance 10.0cm from the origion, (c) the distance s covered by the particle during the first 4.0 and 8.0s , draw the approximate plot s(t) .

(a) At the moment t=0 , a particle leaves the origin and moves in the positive direction of the x-axis. Its velocity is given by v=10-2t . Find the displacement and distance in the first 8s . (b) If v=t-t^(2) , find the displacement and distamce in first 2s.

At the moment t=0 a particle leaves the origin and moves in the positive direction of the x-axis.Its velocity at any time is vecv=vecv_0(1-t/tau) where v_0=10 cm/s and tau =5 s. Find : (a)the x-coordinates of the particle at the instant 6s, 10s and 20s. (b)the instant at which it is a distance 10 cm from the origin. (c )the distance s covered by the particle during the first 4s and 8s.

A particle starts from origin at time t=0 and moves in positive x-direction. Its velocity v varies with times as v = 10that(i) cm/s. The distance covered by the particle in 8 s will be

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

A particle located at x = 0 at time t=0 starts moving along positive x-direction with velocity v that varies as v = asqrt(x) . The displacement of the particle varies with time as :

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

Acceleration of particle moving along the x-axis varies according to the law a=-2v , where a is in m//s^(2) and v is in m//s . At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of time t. (b) Find its position x as function of time t. (c) Find its velocity v as function of its position coordinates. (d) find the maximum distance it can go away from the origin. (e) Will it reach the above-mentioned maximum distance?