In the Young's double slit experiment with sodium light, the slits are `0.589m` apart. The angular separation of the third maximum from the central maximum will be (given `lambda=589mm`)

In the Youngs experiment with sodium light, the slits are 0.589 m apart. What is the angular width of the third maximum ? Given that lambda =589 nm .

In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

n Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

In Young’s Double slit experiment with sodium vapour lamp of wavelength 589 nm and slits 0.589 mm apart, the angular width of central maximum is

In Young's double slit experiment with slit separation d, a monochromatic light of wavelength lamda is used. The angular separation of the fringes is

In a Young's double slit experiment if the slit separation is twice the wavelength of light used then the maximum number of interference maxima is

In Young's double slit experiment, wavelength lambda=5000Å the distance between, the slits is 0.2mm and the screen is at 200cm from the slits. The central maximum is at x=0 The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

In Young's double slit experiment, wavelength lambda=5000Å the distance between, the slits is 0.2mm and the screen is at 200cm from the slits. The central maximum is at x=0 The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

In Young's double slit experiment the wavelenght of light used is 5000 Å the slit -separation is 0.2 mm and the screen is placed at a distance 200 cm from the slits . Central maxima is at x=0 . If the central maxima is assumed as the zeroth bright band then what will be the distance of the third bright band?