If `x^(2//3) -7 x^(1//3) + 10 = 0`, then the set of values of x, is

Let f(x)={x^(3)-x^(2)+10x-5,x 1 The set of values of x=1, is given by

If ((x-2)^(2)(3-x)^(3)(5-x)^(4))/((4-x)^(3))<0, then the exhaustive set of real values of x ,is :

If (1)/(x-3) gt 0 , then what is the set of values that x can take ? (x ne 3) .

If x^(2) + (1)/(x^(2))= 7 and x ne 0 , find the value of : 7x^(3) + 8x- (7)/(x^(3))- (8)/(x)

If an algebraic expression is denoted by f(x) and f(x)=((x+5)(7-x)^(3)(x-1))/((3x+7)^(2)(x-10)x^(5)) then (a) find set of all values of x such that f(x) 0 (c) find least negative integer such that f(x)<0