[" ($) सिद्ध कीजिए कि रेखाएँ "(x-2)/(3)=(y-3)/(4)=(z-4)/(5)" और "],[2x-3y+z=0=x+y+2z+4" बिन्दु "(2,5,7)" पर "],[" एक-दूसरे को मिलती हैं। "]

The angle between the line (x)/(3)=(y)/(4)=(z)/(5) "and the plane " 2x+y-2z=7 is

x-y=3 2x+3y+4z=17 y+2z=7

The (x+4)/(3) = (y+6)/(5) = (z-1)/(-2) and 3x - 2y + z+5 =0 = 2x + 3y + 4z -k are coplanar for k is equal to

If (3)/(2x)+(4)/(3y)=(3)/(5z), then z will be

Prove that the lines (x+4)/3=(y+6)/5=(z-1)/(-2) and 3x-2y+z+5=0=2x+3y+4z-4 are co-planar.

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

If x/2=y/3=z/7 then (2x-5y+4z)/(2y)=

Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " and (x)/(1) = (y)/(2) = (z)/(3) (ii) (x - 3)/(2) = (y + 1)/(-3) = (z - 2)/(4) and (x + 2)/(2) = (y - 4)/(4) = (z + 5)/(2) are perpendicular to each other .