साबित करें कि `( sin alpha+sin beta - sin ( alpha +beta))/( sin alpha +sinbeta + sin ( alpha +beta)) = tan. ( alpha)/(2) tan . ( beta)/(2)`

(sinalpha+sinbeta-sin(alpha+beta))/(sinalpha+sinbeta+sin(alpha+beta))=tan(alpha/2)tan(beta/2)

(without alpha + without beta-sin (alpha + beta)) / (without alpha + without beta + sin (alpha + beta)) = tan ((alpha) / (2)) tan ((beta) / (2))

Show that (sin (alpha + beta))/( sin (alpha + beta)) = 2, given that tan alpha = 2 tan beta.

(cos alpha + cos beta)/( sin alpha - sin beta) + (sin alpha + sin beta)/( cos alpha - cos beta ) =

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

(sin (alpha + beta)) / (sin (alpha-beta)) = (a + b) / (ab) rArr (tan alpha) / (tan beta) =

If 3sin beta = sin(2alpha + beta) , then tan(alpha + beta)-2tan alpha is: