The speed of a satellite that revolves around earth at a height `3R` from earth's surface is (`g=10 m//s^(2)` at the surface of earth, radius of earth `R=6400 km`) in `kms^(-1)`

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R :-

What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R :-

What will be velocity of a satellite revolving around the earth at a height h above surface of earth if radius of earth is R :-

Find the period of revolution of a satellite revolving the earth at a height of 200km above earth's surface ? Radius of earth = 6400 km

A satellite is revolving around the earth at a height of 600 km. find The speed of the satellite. Radius of the earth =6400 km and mass of the earth =6xx10^24kg .

An artificial satellite completes a circle around earth in 120 minutes. Calculate the height of the satellite above the earth's surface. Take, radius of earth = 6,400 km g = 9.8 m//s^(2)

Calculate the speed and period of revolution of a satellite orbiting at a height of 700 km above the earth's surface. Assume the orbit to be circular. Take radius of earth as 6400 km and g at the centre of earth to be 9.8 m//s^2