The work function of a metal is 4 eV. What should be the wavelength of the incident radiation for the emission of photoelectrons of zero velocity ?

The work function of metal is W and lamda is the wavelength of the incident radiation. There is no emission of photoelecrons when

the work function of metal is W and lamda is the wavelength of the incident radiation. There is no emission of photoelecrons when

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

If the work function of a metal is 'phi' and the frequency of the incident light is 'v' , there is no emission of photoelectron if

The work function of a metal is 3.45 eV. Calculate what should be the maximum wavelength of a photon that can eject photoelectrons from the metal ?

Work function of a photosensitive metal is 3eV. The wavelength of incident radiations which can just eject photoelectrons from the metal is

Work function of a metal is 4.0 eV. Find the maximum value of wavelength of a radiation that can emit photoelectrons from the metal.

Work function of a photosensitive metal is 1.875 eV. Calculate the wavelength of incident light, which will just cause the emission of photoelectrons.