For balmer series in the spectrum of atomic hydrogen the wave number of each line is given by `bar(V) = R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` where `R_(H)` is a constant and `n_(1)` and `n_(2)` are integers. Which of the following statements (s), is (are correct)
1. As wave length decreases the lines in the series converge
2. The integer `n_(1)` is equal to 2.
3. The ionisation energy of hydrogen can be calculated from the wave numbers of three lines.
4. The line of shortest wavelength corresponds to = 3.

For balmer series in the spectrum of atomic hydrogen the wave number of each line is given by bar(V)=R_(H)(1)/(n_(1)^(2))-(1)/(n_(2)^(2)) where R_(H) is a constant and n_(1) and n_(2) are integers which of the following statement (S) is / are correct 1 as wavelength decreases the lines in the series converge 2 The integer n_(1) is equal to 2 3 The ionization energy of hydrogen can be calculated from the wave number of these lines 4 The line of longest wavelength corresponds to n_(2)=3

For balmer series in the spectrum of atomic hydrogen the wave number of each line is given by barv=R_H(1/(n_1^2)-1/(n_2^2)) where R_H is a constant and n_1 and n_2 are integers. Which of the following statement is correct? As wavelength decreases the lines in the series converge. The integer n_1 is equal to 2 (iii) The ionisation energy of hydrogen can be calculated from the wave number of these lines. (iv) The line of longest wavelength corresponds to n_2=3

In case of hydrogen spectrum wave number is given by barv = R_H [(1)/(n_2^2) - 1/(n_2^2)] where n_1 lt n_2

The wave length of H_beta line in the Balmer series of hydrogen spectrum is equal to (R = Rydberg constant)

In hydrogen spectrum wave number of different lines is given by 1/lambda=R_(H)[1/n_(i)^(2)-1/n_(f)^(2)] where R_(H)=1.090678xx10^(7)m^(-1) The wavelength of first line of Lyman series would be

The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth orbits from higher energy orbits respectively (as shown in figure) Maximum number of lines produced when an electron jumps from nth level to ground level is equal to (n(n-1))/(2) . For example, in the case of n = 4, number of lines produced is 6. (4 rarr 3, 4 rarr 2, 4 rarr 1, 3 rarr 2, 3 rarr 1, 2 rarr 1) . When an electron returns from n_(2) to n_(1) state, the number of lines in the spectrum will be equal to ((n_(2) - n_(1))(n_(2)-n_(1) +1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(2) then the difference may be expressed in terms of energy of photon as E_(2) - E_(1) = Delta E, lambda = (h c)/(Delta E) . Since h and c are constant, Delta E corresponds to definite energy, thus each transition from one energy level to another will prouce a higher of definite wavelength. THis is actually observed as a line in the spectrum of hydrogen atom. Wave number of the line is given by the formula bar(v) = RZ^(2)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Where R is a Rydberg constant (R = 1.1 xx 10^(7)) (i) First line of a series : it is called .line of logest wavelength. or .line of shortest energy.. (ii) Series limit of last of a series : It is the line of shortest wavelength or line of highest energy. The difference in the wavelength of the 2^(nd) line of Lyman series and last line of Bracket series in a hydrogen sample is

the only electron in the hydrogen atom resides under ordinary conditions in the first orbit. When energy is supplied the electron moves to higher energy orbit depending on the amount of energy absorbed. It emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second. Similarly, Paschen, Breakett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively (as shown in figure). Maximum number of different lines produced when electron jump from nth level to ground level is equal to (n(n-1))/(2). For example in the case of n=4, number of lines produced is 6.(4to3,4to2,4to1,3to2,3to1,2to1). When an electron returns from n_(2) "to"n_(1) state, the number of different lines in the spectrum will be equal to ((n_(2)-n_(1))(n_(2)-n_(1)+1))/(2) If the electron comes back from energy level having energy E_(2) to energy level having energy E_(1), then the difference may be expressed in terms of energy of photon as: E_(2)-E_(1)=DeltaE,lambda=(hc)/(DeltaE),DeltaE=hv(v-"frequency") Since h and c are constants DeltaE corresponds to definite energy: thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom. Wave number of line is given by the formula: barv=RZ^(2)((1)/(n_(1)^(2))-(1)/(n_(2)^(2))) where R is a Rydberg constant (R=1.1xx10^(7)m^(-1)). (i) First line of a series : It is called line of longest wavelength of line of smallest energy'. (ii) Series limit or last line of a series : It is the line of shortest wavelength or line of highest energy. Last line of breakett series for H-atom has wavelength lambda_(1)"Å" and 2nd line of Lyman series has wavelength lambda_(2)"Å" then:

find the wave number of shortest wavelength In Balmer series (Note n_(1) : =2 n_(2) = prop)