In the given figure, `DeltaABC and DeltaDBC` are on the same base BC. If AD intersects BC at O, prove that `(ar(DeltaABC))/(ar(DeltaDBC))=(AO)/(DO)`

In the given figure,Delta ABC and Delta DBC are on the same base BC.If AD intersects BC at O , prove that (ar(Delta ABC))/(ar(Delta DBC))=(AO)/(DO)

In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)

In the same figure, Delta ABC and Delta DBC are on the same base BC . If AD is intersects BC at O, prove that (ar(Delta ABC))/(ar (Delta DBC))=(AO)/(DO)

In figure ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (a r(A B C))/(a r(D B C))=(A O)/(D O) .

In Fig. 6.44, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that (ar (ABC))/( ar (DBC))= (AO )/( DO )

triangleABC and triangleDBC are two triangles on the same base BC. A and D lies on opposite sides of BC. Prove that (ar(triangleABC))/(ar(triangleDBC))= (AO)/(DO)

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at E, show that (i) DeltaABD ~=DeltaACD (ii) DeltaABE~=DeltaACE (iii) AE bisects angleA as well as angleD (iv) AE is the perpendicualr bisector of BC.

In the adjoining figure, triangle ABC and triangleDBC are on the same base BC with A and D on opposite sides of BC such that ar(triangleABC)=ar(triangleDBC) . Show that BC bisect AD.

A point D is taken on the side BC of a DeltaABC such that BD = 2DC. Prove that ar(DeltaABD) = 2 ar (DeltaADC)

In DeltaABC,AD is the bisector of angleA . Then , (ar(DeltaABD))/(ar(DeltaACD))=