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In fig.7.84, DEFG is a square and angleB...

In fig.7.84, DEFG is a square and `angleBAC = 90°`. Prove that:

(i) `DeltaAGF~DeltaDBG` (ii) `DeltaAGF~ DeltaEFC `(iii) `DeltaDBG~ DeltaEFC` (iv) `DE^(2) = BD xx EC`

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