Home
Class 10
MATHS
In Fig. BOA is a diameter of a circle ...

In Fig. BOA is a diameter of a circle with centre O and the tangent at a point P meets BA extended at T . If `angle ABP = 40^@` then `anglePTA ` is equal to `40^@`

Text Solution

Verified by Experts

The correct Answer is:
False `anglePTA=10^@`
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE (Short Answer Questions - II 3 mark)|22 Videos
  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE (Long Answer Questions 4 mark)|12 Videos
  • CIRCLES

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE (Very Short Answer Questions 1 mark)|13 Videos
  • ARITHMETIC PROGRESSIONS

    VK GLOBAL PUBLICATION|Exercise SELF ASSESSMENT TEST|10 Videos
  • COORDINATE GEOMETRY

    VK GLOBAL PUBLICATION|Exercise SELF-ASSESSMENT TEST|10 Videos

Similar Questions

Explore conceptually related problems

In the given figure, O is the centre of a circle, BOA is its diameter and the tangent at the point P meets BA extended at T. If angle PBO = 30^@ ,then angle PTA is equal to

AB is a diameter of a circle with centre O. The tangents at C meets AB produced at Q. if angleCAB=34^(@) , then measure of is angleCBA is

If Fig , AOB is diameter of a circle with centre O and AC is a tangent to the circle at A . If angle BOC = 130^@ , then find angleACO .

AB is a diameter of a circle with centre O and AT is a tangent. If angle AOQ = 58^(@) find angle ATQ .

The tangent at a point A of a circle with centre O intersects the diameter PQ of the circle (when extended) at the point B. If angle BAP = 125^(@) , then angleAQP is equal to :

In the given figure, PQ is a tangent at a point R of the circle with centre O. If angle TRQ = 30^(@) , then angle PRS is equal to

In Figure-2 PQ is tangent to the circle with centre at O , at the point B. If angle AOB = 100^@ , then angle ABP is equal to (A) 50^@ (B) 40^@ (C) 60^@ (D) 80^@