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In Fig. BOA is a diameter of a circle ...

In Fig. BOA is a diameter of a circle with centre O and the tangent at a point P meets BA extended at T . If `angle ABP = 40^@` then `anglePTA ` is equal to `40^@`

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The correct Answer is:
False `anglePTA=10^@`
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AB is a diameter of a circle with centre O. The tangents at C meets AB produced at Q. if angleCAB=34^(@) , then measure of is angleCBA is

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Knowledge Check

  • In the given figure, O is the centre of a circle, BOA is its diameter and the tangent at the point P meets BA extended at T. If angle PBO = 30^@ ,then angle PTA is equal to

    A
    `60^@`
    B
    `30^@`
    C
    `15^@`
    D
    `45^@`

  • In figure , BOA is a diameter of circle and the tangent at point P meets BA produced at. T if angle PBO = 30 ^(@) then angle PTA =

    A
    ` 30 ^(@) `
    B
    ` 60 ^(@) `
    C
    ` 90 ^(@) `
    D
    ` 45 ^(@) `

  • AB is a diameter of a circle with centre O. The tangents at C meets AB produced at Q. If /_CAB = 34^@ , then measure of /_CBA is

    A
    `56^@`
    B
    `34^@`
    C
    `68^@`
    D
    `124^@`

    • Similar Questions

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