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P & Q are centres of circles of radii 9 ...

P & Q are centres of circles of radii 9 cm and 2cm respectively. PQ = 17 cm. R is the centre of the circle of radius x cm which touches the above externally. Given that angle, PRQ is 90. Write an equation in x and solve it.

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The correct Answer is:
`x^(2) + 11x - 102 = 0 , x = 6 cm `
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