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From the top of a building AB, 60 metres...

From the top of a building AB, 60 metres hight, the angles of depression of the top and bottom of a vertical lamp post CD are observed to be `30^(@)` and `60^(@)`, respectively. Find
(i) the horizontal distance between AB and CD.
(ii) the height of the lamp post.

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The correct Answer is:
To solve the problem step by step, we will use the concepts of angles of depression and trigonometry. ### Given: - Height of building AB = 60 meters - Angle of depression to the top of the lamp post (CD) = 30 degrees - Angle of depression to the bottom of the lamp post (CD) = 60 degrees ### Step 1: Understand the Geometry From the top of the building (point A), we can visualize two right triangles: 1. Triangle ABD for the bottom of the lamp post (D). 2. Triangle ABE for the top of the lamp post (C). Let: - \( x \) = horizontal distance between the building (AB) and the lamp post (CD). - \( h \) = height of the lamp post (CD). ### Step 2: Calculate the Horizontal Distance (x) Using triangle ABD: - The angle of depression to point D is 60 degrees. - Therefore, angle ADB = 60 degrees (alternate interior angles). Using the tangent function: \[ \tan(60^\circ) = \frac{AB}{BD} = \frac{60}{x} \] From trigonometric values, we know: \[ \tan(60^\circ) = \sqrt{3} \] Thus, we can write: \[ \sqrt{3} = \frac{60}{x} \] Rearranging gives: \[ x = \frac{60}{\sqrt{3}} = 20\sqrt{3} \] Calculating \( x \): \[ x \approx 20 \times 1.732 = 34.64 \text{ meters} \] ### Step 3: Calculate the Height of the Lamp Post (h) Using triangle ABE: - The angle of depression to point C is 30 degrees. - Therefore, angle AEB = 30 degrees. Using the tangent function: \[ \tan(30^\circ) = \frac{AB}{BE} = \frac{60}{x} \] From trigonometric values, we know: \[ \tan(30^\circ) = \frac{1}{\sqrt{3}} \] Thus, we can write: \[ \frac{1}{\sqrt{3}} = \frac{60}{x} \] Rearranging gives: \[ x = 60\sqrt{3} \] Now, we know that the height of the lamp post (CD) can be calculated as: \[ CD = DE - CE \] Where \( DE = AB = 60 \) meters and \( CE = 20 \) meters (from triangle ABE). So: \[ h = DE - CE = 60 - 20 = 40 \text{ meters} \] ### Final Answers: (i) The horizontal distance between AB and CD is \( 34.64 \) meters. (ii) The height of the lamp post is \( 40 \) meters.
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