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The angle of elevation of the top of a t...

The angle of elevation of the top of a tower from a point` A` due south of the tower is `alpha` and from `B` due east of tower is `beta`. If `AB=d`, show that the height of the tower is `d/sqrt(cot^2 alpha+ cot^2 beta)`.

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The correct Answer is:
`d/(sqrt(cot^(2)alpha+cot^(2)beta))`
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