Home
Class 10
MATHS
The angle of elevation of the top of a t...

The angle of elevation of the top of a tower from a point P on the ground is `alpha`. After walking a distance d meter towards the foot of the tower, angle of elevation is found to be `beta`. Which angle of elevation is greater?

Text Solution

AI Generated Solution

The correct Answer is:
To determine which angle of elevation is greater, we will analyze the situation using trigonometric relationships. Let's break down the problem step by step. ### Step 1: Understanding the Setup Let: - \( AB \) be the height of the tower. - \( P \) be the initial point on the ground from where the angle of elevation is \( \alpha \). - \( C \) be the foot of the tower. - \( D \) be the point after walking \( d \) meters towards the tower, where the angle of elevation is \( \beta \). ### Step 2: Establishing Relationships Using Trigonometry From point \( P \): - The angle of elevation \( \alpha \) gives us the relationship: \[ \tan(\alpha) = \frac{AB}{BC} \] where \( BC \) is the horizontal distance from point \( P \) to the foot of the tower \( C \). From point \( D \): - The angle of elevation \( \beta \) gives us the relationship: \[ \tan(\beta) = \frac{AB}{BD} \] where \( BD \) is the horizontal distance from point \( D \) to the foot of the tower \( C \). ### Step 3: Relating the Distances Since point \( D \) is \( d \) meters closer to the tower than point \( P \), we can express the distances as: \[ BD = BC - d \] ### Step 4: Comparing the Tangents Now, we can rewrite the equations for \( \tan(\alpha) \) and \( \tan(\beta) \): 1. From point \( P \): \[ \tan(\alpha) = \frac{AB}{BC} \] 2. From point \( D \): \[ \tan(\beta) = \frac{AB}{BC - d} \] ### Step 5: Analyzing the Inequality To find out which angle is greater, we need to compare \( \tan(\alpha) \) and \( \tan(\beta) \): - Since \( BC > BD \) (because \( D \) is closer to the tower), we have: \[ BC > BC - d \] - This implies: \[ \frac{AB}{BC} < \frac{AB}{BC - d} \] - Therefore: \[ \tan(\alpha) < \tan(\beta) \] ### Step 6: Conclusion Since \( \tan(\alpha) < \tan(\beta) \), it follows that: \[ \alpha < \beta \] Thus, the angle of elevation \( \beta \) is greater than \( \alpha \).
Promotional Banner

Topper's Solved these Questions

  • HEIGHT AND DISTANCE

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE ( SHORT ANSWER QUESTIONS I)|10 Videos
  • HEIGHT AND DISTANCE

    VK GLOBAL PUBLICATION|Exercise PROFICIENCY EXERCISE ( SHORT ANSWER QUESTIONS II)|32 Videos
  • HEIGHT AND DISTANCE

    VK GLOBAL PUBLICATION|Exercise HOTS (HIGHER ORDER THINKING SKILLS)|9 Videos
  • COORDINATE GEOMETRY

    VK GLOBAL PUBLICATION|Exercise SELF-ASSESSMENT TEST|10 Videos
  • INTRODUCTION TO TRIGONOMETRY

    VK GLOBAL PUBLICATION|Exercise SELF - ASSESSMENT TEST|9 Videos

Similar Questions

Explore conceptually related problems

The angle of elevation of the top of a tower standing on a horizontal plane from a point A is alpha . After walking a distance d towards the foot of the tower the angle of elevation is found to be beta . The height of the tower is (a)d/(cotalpha+cotbeta) (b) d/(cotalpha-cotbeta) (c)d/(tanbeta-t a nalpha) (d) d/(tanbeta+tanalpha)

The angle of elevation of the top of a vertical tower from a point P on the horizontal ground was observed to be alpha . After moving a distance 2 meters from P towards the foot of the tower, the angle of elevation changes to beta . Then the height (in meters) of the tower is :

The angle of elevation of the top of a tower from a point on the ground is 30^(@) . After walking 45 m towards the tower, the angle of elevation becomes 45^(@) . Find the height of the tower.

The angle of elevation of the to of a tower from a point A on the ground is 30^(@) . On moving a distance of 20 meters towards the foot of the tower to a point B, the angle of elevation increases to 60^(@) . What is the height of the tower ?

The angle of elevation of the top of a tower from a point on the ground is 30^(@) . After walking 40sqrt3 m towards the tower, the angle of elevation becomes 60^(@) . Find the height of the tower.

The angle of elevation of top of the tower from a point P on the ground is 30^(@) . If the points is 45 m away from the foot of the tower , then the height of the tower is

The angle of elevation of the top of a tower from a point on the ground,which is 30m away from the foot of the tower is 30o. Find the height of the tower.

The angle of elevation of the top of a tower from a point A on the ground is 30^0dot On moving a distance of 20 metres towards the foot of the tower to a point B the angle of elevation increases to 60^0dot Find the height of the ttower and the distance of the tower from the point A.