The angle of elevation of the top of a pole is `60^(@)`. If the height of the pole increases, the angle of elevation will also increase.

Answer

To determine whether the statement "If the height of the pole increases, the angle of elevation will also increase" is true or false, we can analyze the situation step by step.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- Let \( h \) be the height of the pole.
- Let \( BC \) be the horizontal distance from the observer to the base of the pole.
- The angle of elevation from the observer's point of view to the top of the pole is given as \( 60^\circ \).

2. **Using Trigonometry**:
- In the right triangle formed by the height of the pole, the distance from the observer to the pole, and the line of sight to the top of the pole, we can use the tangent function.
- The tangent of the angle of elevation (\( \theta \)) is defined as:
\[ \tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{h}{BC} \]
- For \( \theta = 60^\circ \):
\[ \tan(60^\circ) = \sqrt{3} \]
- Therefore, we can write:
\[ \tan(60^\circ) = \frac{h}{BC} \implies \sqrt{3} = \frac{h}{BC} \]

3. **Rearranging the Equation**:
- Rearranging gives us:
\[ h = BC \cdot \sqrt{3} \]
- This shows that the height \( h \) is directly proportional to the horizontal distance \( BC \).

4. **Increasing the Height**:
- If we increase the height of the pole by some amount \( x \) (i.e., \( h' = h + x \)), we need to check how this affects the angle of elevation.
- The new angle of elevation \( \alpha \) can be expressed as:
\[ \tan(\alpha) = \frac{h + x}{BC} \]

5. **Comparing Angles**:
- Since \( h + x > h \), it follows that:
\[ \tan(\alpha) > \tan(60^\circ) \]
- Since the tangent function is increasing, this implies:
\[ \alpha > 60^\circ \]

6. **Conclusion**:
- Therefore, if the height of the pole increases, the angle of elevation will also increase. This confirms that the statement is **true**.