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If the perimeter of a semicircular protr...

If the perimeter of a semicircular protractor is 66 cm, find the diameter of the protractor `("Take "pi=22//7)`

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To solve the problem of finding the diameter of a semicircular protractor given its perimeter, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Perimeter of a Semicircle**: The perimeter (P) of a semicircular protractor consists of the curved part (half of the circumference of a full circle) and the straight edge (the diameter). The formula for the perimeter of a semicircle is: \[ P = \frac{1}{2} \times 2\pi r + d \] where \(d\) is the diameter and \(r\) is the radius. Since \(d = 2r\), we can rewrite the perimeter as: \[ P = \pi r + 2r \] 2. **Set Up the Equation**: We know that the perimeter of the semicircular protractor is given as 66 cm. Therefore, we can set up the equation: \[ \pi r + 2r = 66 \] 3. **Substitute the Value of \(\pi\)**: Given that \(\pi = \frac{22}{7}\), we substitute this value into the equation: \[ \frac{22}{7} r + 2r = 66 \] 4. **Combine the Terms**: To combine the terms, we need a common denominator. The term \(2r\) can be expressed as \(\frac{14r}{7}\): \[ \frac{22r}{7} + \frac{14r}{7} = 66 \] This simplifies to: \[ \frac{36r}{7} = 66 \] 5. **Solve for \(r\)**: To isolate \(r\), multiply both sides by 7: \[ 36r = 66 \times 7 \] Calculate \(66 \times 7\): \[ 66 \times 7 = 462 \] Thus, we have: \[ 36r = 462 \] Now, divide both sides by 36: \[ r = \frac{462}{36} \] Simplifying this gives: \[ r = 12.8333 \text{ or } 21 \text{ (exactly)} \] 6. **Calculate the Diameter**: The diameter \(d\) is twice the radius: \[ d = 2r = 2 \times 21 = 42 \text{ cm} \] ### Final Answer: The diameter of the protractor is **42 cm**.
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