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A bag contains 5 red balls and some blue...

A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is thrice that of a red ball, find the number of blue balls in the bag.

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To solve the problem, we need to find the number of blue balls in the bag given that the probability of drawing a blue ball is thrice that of drawing a red ball. ### Step-by-Step Solution: 1. **Identify the Variables**: - Let the number of blue balls be \( x \). - The number of red balls is given as 5. 2. **Calculate Total Balls**: - The total number of balls in the bag is the sum of red and blue balls: \[ \text{Total balls} = x + 5 \] 3. **Calculate the Probability of Drawing a Red Ball**: - The probability of drawing a red ball is given by the formula: \[ P(\text{Red}) = \frac{\text{Number of Red Balls}}{\text{Total Balls}} = \frac{5}{x + 5} \] 4. **Calculate the Probability of Drawing a Blue Ball**: - The probability of drawing a blue ball is: \[ P(\text{Blue}) = \frac{\text{Number of Blue Balls}}{\text{Total Balls}} = \frac{x}{x + 5} \] 5. **Set Up the Equation**: - According to the problem, the probability of drawing a blue ball is thrice that of drawing a red ball: \[ P(\text{Blue}) = 3 \times P(\text{Red}) \] - Substituting the probabilities we calculated: \[ \frac{x}{x + 5} = 3 \times \frac{5}{x + 5} \] 6. **Simplify the Equation**: - Since the denominators are the same, we can multiply both sides by \( x + 5 \) (assuming \( x + 5 \neq 0 \)): \[ x = 15 \] 7. **Conclusion**: - Therefore, the number of blue balls in the bag is: \[ x = 15 \] ### Final Answer: The number of blue balls in the bag is **15**. ---
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