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The king, queen and jack of diamond are ...

The king, queen and jack of diamond are removed from a deck of 52 playing cards and then well shuffled. Now one card is drawn at random from the remaining cards. What is the probability that the card is:
(i) 10 of heart? (ii) a diamond? (iii) a face card?

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The correct Answer is:
To solve the problem step by step, let's analyze each part of the question regarding the probability of drawing specific cards from a modified deck of playing cards. ### Given: - A standard deck has 52 cards. - The king, queen, and jack of diamonds are removed. - Remaining cards = 52 - 3 = 49 cards. ### (i) Probability of drawing the 10 of hearts: 1. **Identify the favorable outcome**: - There is only 1 card that is the 10 of hearts. 2. **Total outcomes**: - After the removal of the three cards, the total number of cards left is 49. 3. **Calculate the probability**: \[ P(\text{10 of hearts}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{1}{49} \] ### (ii) Probability of drawing a diamond: 1. **Identify the favorable outcomes**: - Originally, there are 13 diamonds in a deck. - After removing the king, queen, and jack of diamonds, the remaining diamonds = 13 - 3 = 10. 2. **Total outcomes**: - The total number of cards left is still 49. 3. **Calculate the probability**: \[ P(\text{diamond}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{10}{49} \] ### (iii) Probability of drawing a face card: 1. **Identify the favorable outcomes**: - Face cards include the king, queen, and jack from each suit (hearts, diamonds, spades, clubs). - There are originally 12 face cards (3 from each of the 4 suits). - After removing the king, queen, and jack of diamonds, the remaining face cards = 12 - 3 = 9. 2. **Total outcomes**: - The total number of cards left is still 49. 3. **Calculate the probability**: \[ P(\text{face card}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{9}{49} \] ### Final Answers: - (i) Probability of drawing the 10 of hearts = \(\frac{1}{49}\) - (ii) Probability of drawing a diamond = \(\frac{10}{49}\) - (iii) Probability of drawing a face card = \(\frac{9}{49}\) ---
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