सिद्ध कीजिए की:
` cos A sin (B-C) +cos B sin (C-A) +cos C sin (A-B) =0`

cos(A-D)sin(B-C)+cos(B-D)sin(C-A)+cos(C-D)sin(A-B)=0

(cos A) / (c sin B) + (cos B) / (a sin C) + (cos C) / (b sin A) =

(b-a cos c)sin A=a cos A sin c

If A,B,C,D are four angles then sin (A-B) cos (A+B) + sin B (B-C) .cos (B+C) + sin (C-D) cos (C+D)+ sin (D-A) cos (D+A)=

if A + B + C = pi then (cos A) / (sin B sin C) + (cos B) / (sin C sin A) + (cos C) / (sin A sin B) =

Simplify: 1 + (sin(A - B))/(cos A cosB) + (sin (B - C))/(cos B cos C) + (sin (C - A))/(cos C cos A)

Prove the following : cos(A-D)sin(B-C)+cos(B-D)sin(C-A)+cos(C-D)sin(A-B) = 0

Prove that sin(A+B+C)=sin A cos B cos C+cos A sin B cos C+cos A cos B sin C-sin A sin B sin Ccos(A+B+C)=cos A cos B cos C-cos A sin B sin C-sin A cos B sin C-sin A sin B cos C

In Delta ABC, (cos A)/(c sin B)+(cos B)/( a sin C)+(cos C)/( b sin A) =