The mole fraction of Schottky defect and Frenkel defects, in `NaCl` crystal at `1000K` are respectively. If energy required to produce these defects are `2eV` and `3eV` respectively.
`(1eV=1.6xx10^(-19)J` and `k=1.38xx10^(-23)JK^(-1))`

The number of Schottky defects (n) present in an ionic compound containing N ions at temperature T is given by n = Ne^(-E//2KT) , where E is the energy required to create n Schottky defects and K is the Boltzmann constant, If the mole fraction of Schottky defect in NaCl crystal at 2900 K is X , then calculate -ln(x) , Given: DeltaH of Schottky defect = 2 eV and K = 1.38 xx 10^(-23) J K^(-1) 1 eV = 1.608 xx 10^(-19) J

The number of Schottky defects (n) present in an ionic compound containing N ions at temperature T is given by n = Ne^(-E//2KT) , where E is the energy required to create n Schottky defects and K is the Boltzmann constant, If the mole fraction of Schottky defect in NaCl crystal at 2900 K is X , then calculate -ln(x) , Given: DeltaH of Schottky defect = 2 eV and K = 1.38 xx 10^(-23) J K^(-1) 1 eV = 1.608 xx 10^(-19) J

The number of Schottky defects (n) present in an ionic compound containing N ions at temperature T is given by n = Ne^(-E//2KT) , where E is the energy required to create n Schottky defects and K is the Boltzmann constant, If the mole fraction of Schottky defect in NaCl crystal at 2900 K is X , then calculate -ln(x) , Given: DeltaH of Schottky defect = 2 eV and K = 1.38 xx 10^(-23) J K^(-1) 1 eV = 1.608 xx 10^(-19) J

Calculate the K.E. per mole of oxygen at 27^(@)C . Given N = 6.02 xx 10^(23), k = 1.38 xx 10^(-23) JK^(-1) .

What fraction (n/N) of the lattice sites are vacant at 298 K for a crystal in which the energy required to make a defect is 1 eV. (1 eV = 1.602 xx 10^(-19) J)

Work function of Caesium is 2.14 eV. Find its threshold frequency. h=6.63xx10^(-34)Js,1eV=1.6xx10^(-19) J