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[K(f)" for water is "1.86Kkgmol^(-1)" .I...

[K_(f)" for water is "1.86Kkgmol^(-1)" .If your automobile radiator holds "1.0kg],[" of water,how many grams of ethylene glycol "(C_(2)H_(6)U_(2))" ,must you add to get "],[" the freezing point of the solution lowered to "-2.8" C "C" ? "]

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K_(f) for water is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for water is 1.86 K kg "mol"^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(6)) must you add to get the freezing point of the solution lowered to - 2.8^(@)C ?

K_(f) for water is 1.86 K kg mol^(-1) . IF your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for waer is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

K_(f) for waer is 1.86 K kg mol^(-1) . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C ?

k_f for water is 1.86 k kg mol^(-1) If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to - 2. 8^@C ?

K_f for water is 1.86K kg mol^-1 . If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_2H_6O_2) must you add to get the freezing point of the solution lowered to 0.8^@C ?