Assertion Coefficient of self-induction of an inductor depends upon the rate of change of current passing through it.
Reason From, `e=-L(di)/(dt)`
We can see that, `L=(-e)/((di//dt))or L prop (1)/((di//dt))`

A coil of resistance R and inductance L is joined with a battery of E volt. The current passing through it will be ………..

The self induction of an inductor L = 2mH, and the current through it follows the equation i = e^-t t^2 , then the time at which emf becomes zero

A coil having n turns has self inductance L. Deduce the relation, e=-L*((dI)/(dt))

Assertion : There can be induced e.m.f. in an inductor even if the current through it is zero. Reason : Induced e.m.f. depends upon the rate of change of current rather than the current itself.

If current I passes through a pure inductor of self-inductance L, the energy stored is

The coefficients of self induction of two coils are L_(1) and L_(2) .To induce an of 2 volt in the coil, a change of current of 1A has to be produced in 5 second and 50ms respectively. The ratio of their self inductances L_(1):L_(2) will be

Self induction is the property of a coil by virture of which the coil oppose any change in the strenght of current flowing through it by inducting an e.m.f. in itself. Self induction represents electric inertia which is measured in terms of coefficient of self inductance We can show that L = (phi)/(I) = (-e)/(dI//dt) Read the above passage and answer the following questions : An e.m.f. of 150 microvolt is induced in a coil when current in it changes from 5A ot 1 A in 0.2 sec. what is self inductance of the coil ? (ii) How does self indcution of a coil represent its electric inertia ? (iii) What is them implication of this property in our daily life ?

In an inductor of self-inductance L=2 mH, current changes with time according to relation i=t^(2)e^(-t) . At what time emf is zero ?

In an inductor of self-inductance L=2 mH, current changes with time according to relation i=t^(2)e^(-t) . At what time emf is zero ?