A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

An electron moving in a circular orbit of radius r makes n rotation per secound. The magnetic field produced at the centre has magnitude

A particle having a charge 100 times that of an electron is revolution in a circular path of radius 0.4 m, with 1 rev/s. What is the magnitude of the magnetic field produced at its center?

A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre . The value of the magnetic field produced at the centre will be ( mu_(0)= permeability for vacuum)

In hydrogen atom, an electron is revolving in the orbit of radius 0.53 Å with 6.6xx10^(15) rotations//second . Magnetic field produced at the centre of the orbit is

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

A helium nucleus is moving in a circular path of radius 0.8m. If it takes 2s to complete one revolution. Find out magnetic field produced at the centre of the circle: