An inductor has a resistance R and inductance L .It is connected to an A.C source of e.m.f E_(v) and angular frequency omega , then the current I_(v) in the circuit is

An inductor has a resistance R inductance L . It is connected to an A.C source of e.m.f. E_(V) and angular frequency omega then the current I_(v) in the circuit is

Resistor of resistance R and capacitor of capacitance C are connected in series to an AC source of angular frequency omega . Rms current in the circuit is I. When frequency of the source is changed to one - third of initial value keeping the voltage same then current is found to be halved. Find the ratio of reactance of capacitor to that with resistance at the original frequency omega .

A coil of infuvysnvr 'L' is connected to an a.c. source of emf E and frequency 'f'. The current in the coil is

An inductance L having a resistance R is connected to an alternating source of angular frequency omega .The quality factor Q of the inductance is

A coil having a resistance of 50.0 Omega and an inductance of 0.5 H is connected to an AC source of 110 , v, 50Hz . The rms current in the circuit is

A coil has inductance of 0.4 H and resistance of 8 Omega .It is connected to an AC source with peak emf 4V and frequency 30/pi Hz .The average power dissipated in the circuit is

A resistance R and an inductance L are connected in series in an a.c. circut. If omega is the angular frequency of the source, then the power factor is given by

An inductance L and capacitance C and resistance R are connected in series across an AC source of angular frequency omega . If omega^(2)gt (1)/(LC) then