If `veca, vecb and vecc` are three unit vectors such that `veca xx (vecb xx vecc) = 1/2 vecb , " then " ( vecb and vecc ` being non parallel)

let veca, vecb and vecc be three unit vectors such that veca xx (vecb xx vecc) =sqrt(3)/2 (vecb + vecc) . If vecb is not parallel to vecc , then the angle between veca and vecb is:

let veca, vecb and vecc be three unit vectors such that veca xx (vecb xx vecc) =sqrt(3)/2 (vecb + vecc) . If vecb is not parallel to vecc , then the angle between veca and vecb is:

If veca, vecb and vecc are three non zero vectors such that veca xx vecb = vecc and vecbxx vecc = veca. Prove that veca, vecb and vecc are mutually at right angles and |vecb|=1 and |vecc| =|veca|

If veca, vecb, vecc are the unit vectors such that veca + 2vecb + 2vecc=0 , then |veca xx vecc| is equal to:

If veca , vecb, vecc and vecd are unit vectors such that (veca xx vecb). (veccxx vecd) =1 and veca. Vecc= 1/2 then :

If veca, vecb and vecc are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals

If veca, vecb, vecc are three non-zero vectors such that veca + vecb + vecc=0 and m = veca.vecb + vecb.vecc + vecc.veca , then:

If veca, vecb, vecc are three non-zero vectors such that veca + vecb + vecc=0 and m = veca.vecb + vecb.vecc + vecc.veca , then:

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|