A particle moves along a horizontal line such that its equation of motion is `s(t) = 2t^(3) - 15t^(2) + 24t -2`, s in meters and t in second.
Find the total distance travelled by the particle in the first 2 seconds.

A particle moves along a horizontal line such that its equation of motion is s(t) = 2t^(3) - 15t^(2) + 24t -2 , s in meters and t in second. At what time the particle is at rest

A particle moves along a horizontal line such that its equation of motion is s(t) = 2t^(3) - 15t^(2) + 24t -2 , s in meters and t in second. At what time the particle changes its direction

A particle moves along a horizontal line such that its position at any time t is given by s(t) = t^(3) - 6t^(2) + 9t + 1 , s in meters and t in seconds. At what time the particle is at rest?

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

If S =3t^(3)+9t^(2)+2t+7 , then distance travelled by the particle during the first second of its motion is

The position of a particle moving along a straight line is defined by the relation, x=t^(3)-6t^(2)-15t+40 where x is in meters and t in seconds.The distance travelled by the particle from t=0 to t=2 s is?