At `523 K, 1` litre of partially dissociated `PCI_(5)` at `1` atm weighs ` 2.695g`. Calculate the percentage dissociation of `PCI_(5) "at "523 K`.

PCl_(5) vapour decomposes on heating according to the reaction : PCl_5 (g) hArr PCl_(3) (g) + Cl_(2)(g) The density of a sample of a partially dissociated PCl_(5) at 1.0 atm and 500 K was found 4.8 g/L . Calculate the degree of dissociation and DeltaG^(@) for the reaction at 500 K (Given R=0.082 L atm K^(-1)mol^(-1) ) , R=8.314 JK^(-1) mol^(-1) , In x=2.3031 log_(10)x )

N_(2)O_(4) is 25% dissociated at 37^(@)C and 1 atm . Calculate (i) K_(p) and (ii) the percentage dissociation at 0.1 atm and 37^(@)C .

In an evacuated vessel of capacity 110 litres, 4moles of Argon and 5 moles of PCI_5 were introduced and equilibrium at 250^@C . At equilibrium , the total pressure of the mixture was found to be 4.678 atm. Calculate the degree of dissociation (alpha) "of " PCI_5 and K_p for the reaction, PCI_5 hArr PCI_3 +CI_2 at this temperature.

In an evacuated vessel of capacity 110 litres, 4moles of Argon and 5 moles of PCI_5 were introduced and equilibrium at 250^@C . At equilibrium , the total pressure of the mixture was found to be 4.678 atm. Calculate the degree of dissociation (alpha) "of " PCI_5 and K_p for the reaction, PCI_5 hArr PCI_3 +CI_2 at this temperature.

Asseration : In the dissociation of PCI_(5) at constant pressure and temperature addition of helium at equilibrium increases the dissociation of PCI_(5) . Reason : Helium removes CI_(2) from the field of action.

At a certain temperature, the degree of dissociation of PCI_(5) was found to be 0.25 under a total pressure of 15 atm. The value of K_(P) for the dissociation of PCl_(5) is