यदि त्रिभुज ABC का केन्द्रक G है तब `vec(GA)+vec(GB)+vec(GC)`=

If A, B, C are vertices of a triangle whose position vectors are vec a, vec b and vec c respectively and G is the centroid of Delta ABC, " then " vec(GA) + vec(GB) + vec(GC), is

G is the centroid of a triangle ABC, show that : vec(GA)+vec(GB)+vec(GC)=vec0 .

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If G is the centroid of a triangle ABC, prove that vec(GA)+vec(GB)+vec(GC)=vec(0) .

If G be the centroid of the triangle ABC, then prove that vec(GA)+vec(GB)+vec(GC)=vec(0).

If G is the centroid of a triangle ABC, prove that vec(GA)+vec(GB)+vec(GC) = 0

If G is the centroid of /_\ABC, prove that vec(GA)+vec(GB)+vec(GC) =0. Further if G_1 bet eh centroid of another /_\PQR , show that vec(AP)+vec(BQ)+vec(CR)=3vec(GG_1)

If G is the centroid of /_\ABC, prove that vec(GA)+vec(GB)+vec(GC) =0. Further if G_1 bet eh centroid of another /_\PQR , show that vec(AP)+vec(BQ)+vec(CR)=3vec(GG_1)

In triangle ABC, find vec(AB)+vec(BC)+vec(CA)