There is a current of 40 ampere in a wire of `10^(-6)m^(2)` are of cross-section. If the number of free electron per `m^(3)` is `10^(29)` then the drift velocity will be

There is a current of 40 A in a wire 10^(-6)m^(2) area of cross-section. If the number of free electrons per cubic metre is 10^(29) , then the drift velocity is :

There is a current of 20 amperes in a copper wire of 10^(-6) square metre area of cross-section. If the number of free electrons per cubic metre is 10^(29) then the drift velocity is

There is a current of 0.21 A in a copper wire of area of cross section 10^(-6)m^(2) . If the number of electrons per m^(3) is 18.4xx10^(28) then the drift velocity is ( e=1.6xx10^(-19)C )

Threre is a current of 1.344 a in a copper wire whose area of cross-sectional normal to the length of wire is 1mm^(2) . If the number of free electrons per cm^(2) is 8.4xx10^(28)m^(3) , then the drift velocity would be

A current of 10 ampere passes through a wire having cross-sectional area 1mm^2 . The number of free electron peer 1m^3 of the conductor is 10^(28) . Find the drift velocity of electron.

There is a current of "4.0A" in a wire of cross-sectional area 10^(-6)m^(2) .If the free electron density in wire is 10^(28)m^(-3) ,the drift velocity is :

A copper wire of 10^(-6)m^(2) are of cross section, carries a current of 2A. If the number of electrons per cubic meter is 8xx10^(28) , calculate the current density and average drift velocity.

A current of 10A is maintained in a conductor of cross-section 10^-4m^2 . If the number density of free electrons be 9 xx 10^28 m^-3 , calcualte the drift velocity of free electrons. Given, charge on electron, e = 1.6 xx 10^-19C