In an isosceles triangle altitude from the vertex bisects the base. GIVEN : An isosceles triangle `A B C` such that `A B=A C` and an altitude `A D` from `A` on side `B Cdot` TO PROVE : `D` bisects `B C` i.e. `B D=D Cdot` Figure

In an isosceles triangle altitude from the vertex bisects the base.GIVEN: An isosceles triangle ABC such that AB=AC and an altitude AD from A on side BC. TO PROVE : D bisects BC i.e.BD=DC .Figure

The altitude from the vertex bisect the base in an isosceles triangle

If DeltaA B C is an isosceles triangle such that A B=A C ,\ then altitude A D from A on B C bisects B C (Fig.43).

If A B C is an isosceles triangle such that A B=A C and A D is an altitude from A on B C . Prove that (i) /_B=/_C (ii) A D bisects B C (iii) A D bisects /_A

If A B C is an isosceles triangle such that A B=A C and A D is an altitude from A on B C . Prove that (i) /_B=/_C (ii) A D bisects B C (iii) A D bisects /_A

If A B C is an isosceles triangle such that A B=A C and A D is an altitude from A on B C . Prove that (i) /_B=/_C (ii) A D bisects B C (iii) A D bisects /_A

If the altitude from one vertex of a triangle bisects the opposite side, then the triangle is isosceles. GIVEN : A A B C such that the altitude A D from A on the opposite side B C bisects B C i.e., B D=D Cdot TO PROVE : A B=A C i.e. the triangle A B C is isosceles.

If the altitude from one vertex of a triangle bisects the opposite side, then the triangle is isosceles. GIVEN : A A B C such that the altitude A D from A on the opposite side B C bisects B C i.e., B D=D Cdot TO PROVE : A B=A C i.e. the triangle A B C is isosceles.

In an isosceles triangle A B C with A B=A C and B D_|_A Cdot Prove that B D^2-C D^2=2C DdotA Ddot

If D is any point on the base B C produced, of an isosceles triangle A B C , prove that A D > A B .