दिए गए चित्र में P समांतर चतुर्भुज ABCD के अभ्यंतर में स्थित कोई बिंदु है |दर्शाइए की
`(i) ar (APB) +ar ( PCD) =(1)/(2) ar(ABCD) `
` ar( APD) +ar (PBC) =ar(APB) +ar( PCD) `

In Fig.9.16,P is a point in the interior of a parallelogram ABCD.Show that (i) ar(APB)+ar(PCD)=(1)/(2)ar(ABCD)(ii)ar(APD)+ar(PBC)=ar(APB)+ar(PCD)

IN the figure, P is a point in the interior of a parallelogram ABCD. Show that (i) ar(APB) + ar(PCD) = 1/2 ar (ABCD) (ii) ar (APD) + ar(PBC) = ar(APB) + ar (PCD)

In P is a point in the interior of a parallelogram ABCD. Show that (ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)

In the adjacent figure P is a point inside the parallelogram ABCD. Prove that ar (APD) + ar (PBC) = ar (APB) + ar (PCD)

P is a point in the interior of a parallelogram ABCD. Show that (i) ar (DeltaAPB) +ar (DeltaPCD)=1/2ar (ABCD) (ii) ar(DeltaAPD)+ar (DeltaPBC)=ar(DeltaAPB)+ar(DeltaPCD) (Hint : Throught , P draw a line parallel to AB)

P is a point in the interior of a parallelogram ABCD. Show that (i) ar (DeltaAPB) +ar (DeltaPCD)=1/2ar (ABCD) (ii) ar(DeltaAPD)+ar (DeltaPBC)=ar(DeltaAPB)+ar(DeltaPCD) (Hint : Throught , P draw a line parallel to AB)

P is a point in the interior of a parallelogram ABCD. Show that (i) ar (DeltaAPB) +ar (DeltaPCD)=1/2ar (ABCD) (ii) ar(DeltaAPD)+ar (DeltaPBC)=ar(DeltaAPB)+ar(DeltaPCD) (Hint : Throught , P draw a line parallel to AB)

In a quadrilateral ABCD,P and Q are mid- ponts.Show that ar(AXD)+ar(BYC)=ar(PXQY)

P is a point in the interior of a parallelogram ABCD. Show that ar (Delta APD) + ar ( DeltaPBC) = ar ( DeltaAPB) + ar (DeltaPCD)

If ABCD is a parallelogram,the prove that ar(ABD)=ar(BCD)=ar(ABC)=ar(ACD)=1/2ar(||^(gm)ABCD)