If `A+B+C=180^@`, then show that `sin2A+sin2B+sin2C=4sinAsinBsinC`.

Similar Questions

Explore conceptually related problems

If A+B+C=270^(@) then show that sin2A+sin2B-sin2C=-4sinAsinBcosC

If A+B+C= 180^(@) , then show that sin 2A+ sin 2B+ sin 2C =4 sin A sin B sin C .

If A+B+C=180^(@), then prove that sin2A+sin2B+sin2C=4sin A sin B sin C

If A+B+C=180^(@) , then prove that sin2A+sin2B+sin2C=4 sin A sin B sin C .

If A+B+C=0^(@) then prove that sin2A+sin2B+sin2C=-4sin A sin B sin C

If A+B+C=180^(@), show that sin2A-sin2B-sin2C=-4sin A cos B cos C

If (A+B+C)=180^(@) , then what is Sin2A-Sin2B-Sin2C=

If A+B+C=0 , then prove that sin 2A + sin 2B+ sin 2C=-4sin A sin B sin C .

If A+B+C =180^(@) then prove that sin 2A + sin 2B+ sin 2C = 4 sin A sin B sin C

If A + B + C = 180^@ , then prove that sin 2 A+ sin 2B + sin 2C = 4 sin A sin B sin C