In a Young's double slit experiment, the separation between the two slits is d and the wavelength of the light is `lamda`. The intensity of light falling on slit 1 is four times the intensity of light falling on slit 2. Choose the correct choice (s).

In a Young's double slit experiment,the separation betwen the two slits is d and the wavelength of the light is lambda .The intensity of light falling on the slit 1 is four times the intesntiy of light falling on slit 2.Choose the correct choice(s).

In Young's double slit experiment the distance between the two slits is d and wavelength of the light used is lambda . The angular width of the fringe

In Young’s double slit experiment, first dark fringe occurs directly opposite to slit. Wavelength of light used is

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is

In a Young's double slit experiment if the slit separation is twice the wavelength of light used then the maximum number of interference maxima is

In a double slit experiment the separation between the slits is d and distance of screen from slits is D. If the wavelenth of light used is lamda and I is the intensity of central bright fringe, then intensity at distance x from central maximum is given by

In a double slit experiment, the separation between the slits is d and distance of the screen from slits is D. If the wavelength of light used is lambda and I is theintensity of central bright fringe, then intensity at distance from central maximum is

The intensity at the maximum in a Young's double slit experiment is I_(0) . Separation between two slits is d = 5lambda , where lambda is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10 d?