A particle moves along `x`-axis. The position of the particle at time `t` is given as `x=t^(3)-9t^(2)+24t+1`. Find the distance traveled in first `5` seconds.

The position of a particle along x-axis at time t is given by x=1 + t-t^2 . The distance travelled by the particle in first 2 seconds is

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

The position of a particle moving rectilinearly is given by x = t^3 - 3 t^2 - 10 . Find the distance travelled by the particle in the first 4 seconds starting from t = 0 .

A particle moves along a horizontal line such that its position at any time t is given by s(t) = t^(3) - 6t^(2) + 9t + 1 , s in meters and t in seconds. At what time the particle is at rest?

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of a particle moving along x-axis is given by x=2+8t-4t^(2) . The distance travelled by the particle from t=0 to t=2 is:-

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :