दीर्घवृत्त `4x^(2)+9y^(2)-8x-36y+4=0` कि उत्केन्द्रता ज्ञात कीजिए।

The transformed equation of 4x^(2) + 9y^(2) - 8x + 36y + 4 = 0 when the axes are translated to (1, -2) is ax^(2) + by^(2) = c . Then desending order of a, b, c

The transformed equation of 4x^(2) + 9y^(2) - 8x + 36 y + 4 = 0 when the axes are translated to the point (1,-2) is

Find the point to which the origin has to be shifted to eliminate x and y terms (to remove first degree terms) in the following equations (i) 4x^(2) + 9y^(2) - 8x + 36 y + 4 = 0 (ii) x^(2) + y^(2) - 2ax - 4ay + a^(2) = 0

To remove the first degree terms in the following equations origin should be shifted to the another point then calculate the new origins from list - II {:(" List - I "," List - II "),("(A) "x^(2)-y^(2)+2x+4y=0,"(1) (5,-7) "),("(B) "4x^(2) +9y^(2)-8x+36y + 4 = 0,"(2) (1,-2) "),("(C) "x^(2) + 3y^(2) + 2x + 12y + 1 = 0,"(3) (-1,2) "),("(D) "2(x-5)^(2)+3(y+7)^(2)=10,"(4) (-1,-2) "),(,"(5) (-5,7) "):} The correct matching is

If 8x^2+y^2- 12x - 4xy + 9= 0 , then the value of (14x - 5y) is: यदि 8x^2+y^2- 12x - 4xy + 9= 0 है, तो (14x - 5y) का मान ज्ञात करें |

The transformed equation of 4x^(2) + 9y^(2) - 8x + 36y+4=0 when the axes are translated to the point (1,-2) is

If C is the center and A,B are two points on the conic 4x^(2)+9y^(2)-8x-36y+4=0 such that /_ACB=(pi)/(2), then prove that (1)/(CA^(2))+(1)/(CB^(2))=(13)/(36) .

To remvoe the first dgree terms in the equation 4x^(2)+9y^(2)-8x+36y+4=0 , the origin in shifted to the point