The molecular weight of a gas which diffuses through a porous plug at `1//6^(th)` of the speed of hydrogen under identical condition is:

The molecular weight of a gas which diffuses through a porous plug of 1/6th of the speed of hydrogen under identical conditions is :

A gas with molecular formula C_(n)H_(2n + 2) diffuses through a porous plug at a rate 1//6th of the rate of diffusion of hydrogen gas under similar condtition. The formula of the gas is:

What is the ratio of the rate of diffusion of helium gas to that of oxygen under identical conditions?

If 4g of oxygen diffuses through a very narrow hole, how much hydrogen would have diffused under identical conditions?

If 4g of oxygen diffuses through a very narrow hole, how much hydrogen would have diffused under identical conditions?

Molecular weight of a gas that diffuses twice as rapidly as the gas with molecular weight 64 is