The Henry's Law constant for oxygen dissolved in water is `4.34xx10^(4) atm at 25^(@)C`. If partial pressure of exygen in are is 0.2 atm. Under ordinary atmospheric conditions, calculate the concentration (in moles/litre) of dissolved oxygen in water in equilibrium with air at `25^(@)C`.

The Henry's Law constant for oxygen dissolved in water is 4.34 xx 10 ^(4)atm ( mol /L) at 25^(@) C . If the partial pressure of oxygen in air is 0.2 atm under ordinary atmospheric condition calculate the concentration (in mol/litre ) of dissolved oxygen in water equilibrium with air at 25^(@) C

Henry law constant for oxygen dissolved in water is 4.34 xx 10^(4) atm at 25^(@) C . If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at 25^@C .

Henry law constant for oxygen dissolved in water is 4.34 xx 10^(4) atm at 25^(@) C . If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at 25^@C .

Henry law constant for oxygen dissolved in water is 4.34 xx 10^(4) atm at 25^(@) C . If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at 25^@C .

The partial pressure of oxygen in air is 0.2 atm. What is the conentration of dissolved oxygen in water in equilibrium with air at 25^(@) C ? ( K_(H) for oxgyen at 25^(@)C is 4.34 cc 10^(4) atm).

The K_H for the solution of oxygen dissolved in water is 4xx 10^(4) atm at a given temperature . If the partial pressure of oxygen in air is 0.4 atm the mole fraction of oxygen in solution is