Prove that the rate of diffusion of a gas is inversely proportional to the square root of its density.

Assertion: A lighter gas diffuses more rapidly than heavier gas. Reason: At a given temperature, the rate of diffusion of a gas is inversely proportional to the square root of its density.

Assertion: A lighter gas diffuse more rapidly than a heavier gas. Reason: At a given temperature, the rate of diffusion of a gas is inversely proportional to the square root of its density.

Assertion: A lighter gas diffuses more rapidly than heavier gas. Reason: At a given temperature and pressure, the rate of diffusion of a gas is inversely proportional to the square root of its density.

Statement-1. Ammonia has lower molecular mass than N_(2) . Statement-2. At a given temperature te rate of diffusion is inversely proportional to the square root of its density.

Statement-1. Ammonia has lower molecular mass than N_(2) . Statement-2. At a given temperature te rate of diffusion is inversely proportional to the square root of its density.

The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion prop (1)/(sqrt(d)) If r_(1) and r_(2) represent the rates of diffusion of two gases and d_(1) and d_(2) are their respective densities, then r_(1)/(r_(2))=sqrt((d_(2))/(d_(1))) r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2)) (V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1))) V prop n (where n is no of moles) V_(1) prop n_(1) and V_(2) prop n_(2) If some moles of O_(2) diffuse in 18 sec and same moles of other gas diffuse in 45sec then what is the molecular weight of the unknown gas ? .