Obtain `P(barA+ B), P(A + barB)` in terms of `P(A), P(B) and P(AB)`, where `barA` is the event complementary to the event A .

Obtain P(bar(A) + B) , P(A+ bar(B)) in terms of P(A) , P(B) and P(AB), where bar(A) is the event complementary to the event A.

For events A and B P(bar(A cup B))= (1)/(6), P(barA)= (1)/(4) and P(A cap B) = (1)/(4) , Where (barA) is the complementary event of A then events A and B are

Let A and B be two events, such that P(bar(A cup B))=(1)/(6), P(A cap B)=(1)/(4) and P(barA)=(1)/(4) , where barA stands for complement of event A. Then events A and B are :

Let A and B be two events such that P (bar(AuuB))=1/6, P(AnnB)=1/4and P(barA)=1/4,where barA stands for the complement of the event A. Then the events A and B are

Let A and B be two events such that P (bar(AuuB))=1/6, P(AnnB)=1/4and P(barA)=1/4,where barA stands for the complement of the event A. Then the events A and B are