Reading shown in two spring balances `S_(1)` and `S_(2)` is 90kg and 30kg respectively and lft is accelerating upwards with acceleration `10m//s^(2).S_(1)` in elongated and `S_(2)` is compressed. The mass is stationary with respect to life. Then the mass of the block will be

The apparent weight of the body, when it is travelling upwards with an acceleration of 2m//s^(2) and mass is 10 kg , will be

The mass of a lift is 600 kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is-

A lift of mass 200 kg is moving upward with an acceleration of 3m//s^(2) . If g=10 m//s^(2) then the tension of string of the lift will be :

A block of mass 1 kg and density 0.8g//cm^(3) is held stationary with the help of a string as shown in figure. The tank is accelerating vertically upwards with an acceleration a =1.0m//s^(2) . Find (a) the tension in the string, (b) if the string is now cut find the acceleration of block. (Take g=10m//s^(2) and density of water =10^(3)kg//m^(3)) .

A block of mass 1 kg and density 0.8g//cm^(3) is held stationary with the help of a string as shown in figure. The tank is accelerating vertically upwards with an acceleration a =1.0m//s^(2) . Find (a) the tension in the string, (b) if the string is now cut find the acceleration of block. (Take g=10m//s^(2) and density of water =10^(3)kg//m^(3)) .

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

Two blocks with masses M_(1) and M_(2) of 10 kg and 20 kg respectively are placed as in fig. mu_(s)=0.2 between all surfaces, then tension in string and acceleration of M_(2) block will be:

The magnitudes of accelerations of blocks of mass 2 kg and 4 kg are respectively . ( Pulleys and threads are massless) ( g = 10 m//s^(2 )

A body of mass 50 kg is hung by a spring balance in a lift. Calculate the reading of the balance when : The lift is ascending with an acceleration of 2m//s^(2) .